2n^2-10n=28

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Solution for 2n^2-10n=28 equation:


Simplifying
2n2 + -10n = 28

Reorder the terms:
-10n + 2n2 = 28

Solving
-10n + 2n2 = 28

Solving for variable 'n'.

Reorder the terms:
-28 + -10n + 2n2 = 28 + -28

Combine like terms: 28 + -28 = 0
-28 + -10n + 2n2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-14 + -5n + n2) = 0

Factor a trinomial.
2((-2 + -1n)(7 + -1n)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-2 + -1n)' equal to zero and attempt to solve: Simplifying -2 + -1n = 0 Solving -2 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1n = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1n = 0 + 2 -1n = 0 + 2 Combine like terms: 0 + 2 = 2 -1n = 2 Divide each side by '-1'. n = -2 Simplifying n = -2

Subproblem 2

Set the factor '(7 + -1n)' equal to zero and attempt to solve: Simplifying 7 + -1n = 0 Solving 7 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1n = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1n = 0 + -7 -1n = 0 + -7 Combine like terms: 0 + -7 = -7 -1n = -7 Divide each side by '-1'. n = 7 Simplifying n = 7

Solution

n = {-2, 7}

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